
algebra precalculus - How to remember the derivatives of inverse ...
Mar 6, 2021 · I remember the derivatives of trig functions by naming 3x basic right triangles in a specific way and using ONE simple multiplication. Just wondering if there are similar approaches to …
Can you propose any hack for remembering the common derivative …
May 22, 2021 · Here is a trick I use to remember the derivatives and antiderivatives of trigonometric functions. If you know that sin′(x) sec′(x) tan′(x) = cos(x) = sec(x) tan(x) =sec2(x), sin (x) = cos (x) sec …
Derivative of inverse trig function - Mathematics Stack Exchange
Jan 10, 2019 · I'm a bit confused about how the inverse trig functions are differentiated. From a website: We have the following relationship between the inverse sine function and the sine function. $$\\sin...
calculus - Trying to derive an inverse trigonometric function ...
Feb 21, 2011 · The general way is to know the derivatives of the inverse trigonometric functions, and then apply the Chain Rule.
calculus - Purely geometric proof of inverse trigonometric functions ...
Jul 17, 2020 · Purely geometric proof of inverse trigonometric functions derivatives Ask Question Asked 5 years, 5 months ago Modified 5 years, 5 months ago
Why the derivative of inverse secant has an absolute value?
Jun 27, 2020 · Why the derivative of inverse secant has an absolute value? Ask Question Asked 5 years, 5 months ago Modified 4 years, 4 months ago
calculus - Why do we take positive square roots when proving the ...
Nov 10, 2017 · Why do we take positive square roots when proving the derivatives of the trig functions? Ask Question Asked 8 years, 1 month ago Modified 8 years, 1 month ago
What is the difference between inverse and reciprocal?
Feb 2, 2020 · The derivative of the inverse function is dy dx = 1 x d y d x = 1 x. These might not seem to be reciprocals, until you realize that x x and y y mean something different in each function.
Why does the derivative of sine only work for radians?
Jun 26, 2015 · I'm still struggling to understand why the derivative of sine only works for radians. I had always thought that radians and degrees were both arbitrary units of measurement, and just now I'm …
How to derive inverse hyperbolic trigonometric functions
3 Use the identity $\sin x = -i\sinh x$. Then your formula gives $\sinh x =\ln| \sqrt {x^2+1}+x|$. By restricting hyperbolic sine to the reals and, thus, its inverse to positive reals, you can drop the …