
Question #a52c4 - Socratic
MnO_4^(2-) +4H_2O + 2S^(2-) =2 S+ Mn^(2+) + 8 OH^- Mn reduceds itself from N° of oxidation +6 to +2 buying 4 electrons. To balance the semireaction i write 8 OH^- on the right because the reaction …
Question #cb195 - Socratic
Basic. [H_3O^+]= [OH^-]=10^ {-7} M is a neutral solution. With higher [H_3O^+] you have [OH^-] and an acidic solution. With lower [H_3O^+] you get higher [OH^-] and you have a basic solution.
Question #c0883 - Socratic
"Oh! Now I remember where I put my wallet." "Oh" here is the interjection among your examples. An interjection is a word or expression that utters on its own and expresses a spontaneous feeling or …
Question #97503 - Socratic
Here's what I get. The general equation for the dissociation of a carboxylic acid is "R-COOH + H"_2"O" ⇌ "R-COO"^"-" + "H"_3"O"^+ All we have to do is write the ...
Question #50782 - Socratic
sf(pH=7.04) This is a very dilute solution of NaOH so I would expect the pH to be 7 or very slightly above. Because the concentration is so low we must also take into account the ions that are formed …
Question #ccabf - Socratic
Nov 23, 2015 · Because N aOH → N a+ + OH − and N i2+ + 2OH −→N i(OH)2 Total Mols of N aOH: 60mL ⋅ 0.45M ol/L = 27mM ol of N aOH (dont forget the m for milli=one thousandth) This will produce …
Question #019dd - Socratic
Only (C) is fully correct. As you can see, steam typically reacts with alkenes by adding H on one double-bonded atom and OH on the other. But there are two possible choices for which atom gets the single …
Question #0a25a - Socratic
Mar 20, 2017 · Lithium hydroxide has a mass of 24 g per mole, so 2.50 g is 0.104 mole. Dissolve this in 1.50 L, and the concentration is [LiOH] = 0.104 mol -: 1.50 L = 0.0694 "mol"/L Since LiOH is a strong …
Question #7c802 + Example - Socratic
Oxides that form neither an acid nor a base, in combination with water. Acid oxides will react with water to ultimately give off H^+: Sulphur trioxide SO_3 will form sulfuric acid: SO_3 (g) + H_2O (l) …
Question #74006 - Socratic
(d) is the correct option. CH_3CH(OH)CH_2CH_2CH_3 (pentan-2-ol) being secondary alcohol on oxidation first tansformed into ketone. CH_3CH(OH)CH_2CH_2CH_3stackrel([O])-> …